-5(8-y)=6(2y+1/3)

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Solution for -5(8-y)=6(2y+1/3) equation:



-5(8-y)=6(2y+1/3)
We move all terms to the left:
-5(8-y)-(6(2y+1/3))=0
We add all the numbers together, and all the variables
-5(-1y+8)-(6(+2y+1/3))=0
We multiply parentheses
5y-(6(+2y+1/3))-40=0
We multiply all the terms by the denominator
5y*3))-(6(+2y+1-40*3))=0
We add all the numbers together, and all the variables
5y*3))-(6(2y-119))=0
We add all the numbers together, and all the variables
5y*3))-(6(2y=0
Wy multiply elements
15y^2=0
a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{30}=0$

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