-5(b+2)=-(12b-11)

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Solution for -5(b+2)=-(12b-11) equation: 



-5(b+2)=-(12b-11)

We move all terms to the left:

-5(b+2)-(-(12b-11))=0

We multiply parentheses

-5b-(-(12b-11))-10=0



We calculate terms in parentheses: -(-(12b-11)), so:

-(12b-11)

We get rid of parentheses

-12b+11

Back to the equation:

-(-12b+11)



We get rid of parentheses

-5b+12b-11-10=0

We add all the numbers together, and all the variables

7b-21=0

We move all terms containing b to the left, all other terms to the right

7b=21

b=21/7

b=3

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