-5(g-12)-g=-6(-g+2)

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Solution for -5(g-12)-g=-6(-g+2) equation: 



-5(g-12)-g=-6(-g+2)

We move all terms to the left:

-5(g-12)-g-(-6(-g+2))=0

We add all the numbers together, and all the variables

-5(g-12)-g-(-6(-1g+2))=0

We add all the numbers together, and all the variables

-1g-5(g-12)-(-6(-1g+2))=0

We multiply parentheses

-1g-5g-(-6(-1g+2))+60=0



We calculate terms in parentheses: -(-6(-1g+2)), so:

-6(-1g+2)

We multiply parentheses

6g-12

Back to the equation:

-(6g-12)



We add all the numbers together, and all the variables

-6g-(6g-12)+60=0

We get rid of parentheses

-6g-6g+12+60=0

We add all the numbers together, and all the variables

-12g+72=0

We move all terms containing g to the left, all other terms to the right

-12g=-72

g=-72/-12

g=+6

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