-5(k+2)=13-(k-11)

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Solution for -5(k+2)=13-(k-11) equation: 



-5(k+2)=13-(k-11)

We move all terms to the left:

-5(k+2)-(13-(k-11))=0

We multiply parentheses

-5k-(13-(k-11))-10=0



We calculate terms in parentheses: -(13-(k-11)), so:

13-(k-11)

determiningTheFunctionDomain
-(k-11)+13

We get rid of parentheses

-k+11+13

We add all the numbers together, and all the variables

-1k+24

Back to the equation:

-(-1k+24)



We get rid of parentheses

-5k+1k-24-10=0

We add all the numbers together, and all the variables

-4k-34=0

We move all terms containing k to the left, all other terms to the right

-4k=34

k=34/-4

k=-8+1/2

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