-5(k+2)=13=(k-1)

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Solution for -5(k+2)=13=(k-1) equation: 



-5(k+2)=13=(k-1)

We move all terms to the left:

-5(k+2)-(13)=0

We multiply parentheses

-5k-10-13=0

We add all the numbers together, and all the variables

-5k-23=0

We move all terms containing k to the left, all other terms to the right

-5k=23

k=23/-5

k=-4+3/5

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