-5(k+2)=3(k+2)-20

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Solution for -5(k+2)=3(k+2)-20 equation: 



-5(k+2)=3(k+2)-20

We move all terms to the left:

-5(k+2)-(3(k+2)-20)=0

We multiply parentheses

-5k-(3(k+2)-20)-10=0



We calculate terms in parentheses: -(3(k+2)-20), so:

3(k+2)-20

We multiply parentheses

3k+6-20

We add all the numbers together, and all the variables

3k-14

Back to the equation:

-(3k-14)



We get rid of parentheses

-5k-3k+14-10=0

We add all the numbers together, and all the variables

-8k+4=0

We move all terms containing k to the left, all other terms to the right

-8k=-4

k=-4/-8

k=1/2

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