-5(k+2)=3-(k-1)

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Solution for -5(k+2)=3-(k-1) equation: 



-5(k+2)=3-(k-1)

We move all terms to the left:

-5(k+2)-(3-(k-1))=0

We multiply parentheses

-5k-(3-(k-1))-10=0



We calculate terms in parentheses: -(3-(k-1)), so:

3-(k-1)

determiningTheFunctionDomain
-(k-1)+3

We get rid of parentheses

-k+1+3

We add all the numbers together, and all the variables

-1k+4

Back to the equation:

-(-1k+4)



We get rid of parentheses

-5k+1k-4-10=0

We add all the numbers together, and all the variables

-4k-14=0

We move all terms containing k to the left, all other terms to the right

-4k=14

k=14/-4

k=-3+1/2

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