-5(r-3)+8r=2(5+4r)

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Solution for -5(r-3)+8r=2(5+4r) equation: 



-5(r-3)+8r=2(5+4r)

We move all terms to the left:

-5(r-3)+8r-(2(5+4r))=0

We add all the numbers together, and all the variables

-5(r-3)+8r-(2(4r+5))=0

We add all the numbers together, and all the variables

8r-5(r-3)-(2(4r+5))=0

We multiply parentheses

8r-5r-(2(4r+5))+15=0



We calculate terms in parentheses: -(2(4r+5)), so:

2(4r+5)

We multiply parentheses

8r+10

Back to the equation:

-(8r+10)



We add all the numbers together, and all the variables

3r-(8r+10)+15=0

We get rid of parentheses

3r-8r-10+15=0

We add all the numbers together, and all the variables

-5r+5=0

We move all terms containing r to the left, all other terms to the right

-5r=-5

r=-5/-5

r=1

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