-5(s+2)=2(1-3s)

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Solution for -5(s+2)=2(1-3s) equation: 



-5(s+2)=2(1-3s)

We move all terms to the left:

-5(s+2)-(2(1-3s))=0

We add all the numbers together, and all the variables

-5(s+2)-(2(-3s+1))=0

We multiply parentheses

-5s-(2(-3s+1))-10=0



We calculate terms in parentheses: -(2(-3s+1)), so:

2(-3s+1)

We multiply parentheses

-6s+2

Back to the equation:

-(-6s+2)



We get rid of parentheses

-5s+6s-2-10=0

We add all the numbers together, and all the variables

s-12=0

We move all terms containing s to the left, all other terms to the right

s=12

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