-5(t+3)-t-4=-6(t+5)+11

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Solution for -5(t+3)-t-4=-6(t+5)+11 equation: 



-5(t+3)-t-4=-6(t+5)+11

We move all terms to the left:

-5(t+3)-t-4-(-6(t+5)+11)=0

We add all the numbers together, and all the variables

-1t-5(t+3)-(-6(t+5)+11)-4=0

We multiply parentheses

-1t-5t-(-6(t+5)+11)-15-4=0



We calculate terms in parentheses: -(-6(t+5)+11), so:

-6(t+5)+11

We multiply parentheses

-6t-30+11

We add all the numbers together, and all the variables

-6t-19

Back to the equation:

-(-6t-19)



We add all the numbers together, and all the variables

-6t-(-6t-19)-19=0

We get rid of parentheses

-6t+6t+19-19=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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