-5(u+1)=3u+7+2(3u+)

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Solution for -5(u+1)=3u+7+2(3u+) equation: 



-5(u+1)=3u+7+2(3u+)

We move all terms to the left:

-5(u+1)-(3u+7+2(3u+))=0

We add all the numbers together, and all the variables

-5(u+1)-(3u+7+2(+3u))=0

We multiply parentheses

-5u-(3u+7+2(+3u))-5=0



We calculate terms in parentheses: -(3u+7+2(+3u)), so:

3u+7+2(+3u)

determiningTheFunctionDomain
3u+2(+3u)+7

We multiply parentheses

3u+6u+7

We add all the numbers together, and all the variables

9u+7

Back to the equation:

-(9u+7)



We get rid of parentheses

-5u-9u-7-5=0

We add all the numbers together, and all the variables

-14u-12=0

We move all terms containing u to the left, all other terms to the right

-14u=12

u=12/-14

u=-6/7

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