-5(u+1)=3u-3+2(2u+4)

Solution for -5(u+1)=3u-3+2(2u+4) equation:

-5(u+1)=3u-3+2(2u+4)

We move all terms to the left:

-5(u+1)-(3u-3+2(2u+4))=0

We multiply parentheses

-5u-(3u-3+2(2u+4))-5=0


We calculate terms in parentheses: -(3u-3+2(2u+4)), so:

3u-3+2(2u+4)

determiningTheFunctionDomain
3u+2(2u+4)-3

We multiply parentheses

3u+4u+8-3

We add all the numbers together, and all the variables

7u+5

Back to the equation:

-(7u+5)


We get rid of parentheses

-5u-7u-5-5=0

We add all the numbers together, and all the variables

-12u-10=0

We move all terms containing u to the left, all other terms to the right

-12u=10

u=10/-12

u=-5/6