-5(u+1)=9u-8+2(2u+3)

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Solution for -5(u+1)=9u-8+2(2u+3) equation: 



-5(u+1)=9u-8+2(2u+3)

We move all terms to the left:

-5(u+1)-(9u-8+2(2u+3))=0

We multiply parentheses

-5u-(9u-8+2(2u+3))-5=0



We calculate terms in parentheses: -(9u-8+2(2u+3)), so:

9u-8+2(2u+3)

determiningTheFunctionDomain
9u+2(2u+3)-8

We multiply parentheses

9u+4u+6-8

We add all the numbers together, and all the variables

13u-2

Back to the equation:

-(13u-2)



We get rid of parentheses

-5u-13u+2-5=0

We add all the numbers together, and all the variables

-18u-3=0

We move all terms containing u to the left, all other terms to the right

-18u=3

u=3/-18

u=-1/6

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