-5(u+2)=4u-3+3(2u+1)

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Solution for -5(u+2)=4u-3+3(2u+1) equation: 



-5(u+2)=4u-3+3(2u+1)

We move all terms to the left:

-5(u+2)-(4u-3+3(2u+1))=0

We multiply parentheses

-5u-(4u-3+3(2u+1))-10=0



We calculate terms in parentheses: -(4u-3+3(2u+1)), so:

4u-3+3(2u+1)

determiningTheFunctionDomain
4u+3(2u+1)-3

We multiply parentheses

4u+6u+3-3

We add all the numbers together, and all the variables

10u

Back to the equation:

-(10u)



We add all the numbers together, and all the variables

-15u-10=0

We move all terms containing u to the left, all other terms to the right

-15u=10

u=10/-15

u=-2/3

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