-5(u+2)=u-6+2(2u+5)

Solution for -5(u+2)=u-6+2(2u+5) equation:

-5(u+2)=u-6+2(2u+5)

We move all terms to the left:

-5(u+2)-(u-6+2(2u+5))=0

We multiply parentheses

-5u-(u-6+2(2u+5))-10=0


We calculate terms in parentheses: -(u-6+2(2u+5)), so:

u-6+2(2u+5)

determiningTheFunctionDomain
u+2(2u+5)-6

We multiply parentheses

u+4u+10-6

We add all the numbers together, and all the variables

5u+4

Back to the equation:

-(5u+4)


We get rid of parentheses

-5u-5u-4-10=0

We add all the numbers together, and all the variables

-10u-14=0

We move all terms containing u to the left, all other terms to the right

-10u=14

u=14/-10

u=-1+2/5