-5(u+4)=5u-6+2(2u+1)

Solution for -5(u+4)=5u-6+2(2u+1) equation:

-5(u+4)=5u-6+2(2u+1)

We move all terms to the left:

-5(u+4)-(5u-6+2(2u+1))=0

We multiply parentheses

-5u-(5u-6+2(2u+1))-20=0


We calculate terms in parentheses: -(5u-6+2(2u+1)), so:

5u-6+2(2u+1)

determiningTheFunctionDomain
5u+2(2u+1)-6

We multiply parentheses

5u+4u+2-6

We add all the numbers together, and all the variables

9u-4

Back to the equation:

-(9u-4)


We get rid of parentheses

-5u-9u+4-20=0

We add all the numbers together, and all the variables

-14u-16=0

We move all terms containing u to the left, all other terms to the right

-14u=16

u=16/-14

u=-1+1/7