-5(u+5)+32=3(7-u)

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Solution for -5(u+5)+32=3(7-u) equation: 



-5(u+5)+32=3(7-u)

We move all terms to the left:

-5(u+5)+32-(3(7-u))=0

We add all the numbers together, and all the variables

-5(u+5)-(3(-1u+7))+32=0

We multiply parentheses

-5u-(3(-1u+7))-25+32=0



We calculate terms in parentheses: -(3(-1u+7)), so:

3(-1u+7)

We multiply parentheses

-3u+21

Back to the equation:

-(-3u+21)



We add all the numbers together, and all the variables

-5u-(-3u+21)+7=0

We get rid of parentheses

-5u+3u-21+7=0

We add all the numbers together, and all the variables

-2u-14=0

We move all terms containing u to the left, all other terms to the right

-2u=14

u=14/-2

u=-7

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