-5(v+1)=5v-4+2(4v+4)

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Solution for -5(v+1)=5v-4+2(4v+4) equation: 



-5(v+1)=5v-4+2(4v+4)

We move all terms to the left:

-5(v+1)-(5v-4+2(4v+4))=0

We multiply parentheses

-5v-(5v-4+2(4v+4))-5=0



We calculate terms in parentheses: -(5v-4+2(4v+4)), so:

5v-4+2(4v+4)

determiningTheFunctionDomain
5v+2(4v+4)-4

We multiply parentheses

5v+8v+8-4

We add all the numbers together, and all the variables

13v+4

Back to the equation:

-(13v+4)



We get rid of parentheses

-5v-13v-4-5=0

We add all the numbers together, and all the variables

-18v-9=0

We move all terms containing v to the left, all other terms to the right

-18v=9

v=9/-18

v=-1/2

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