-5(v+2)=4v-7+3(3v+4)

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Solution for -5(v+2)=4v-7+3(3v+4) equation:



-5(v+2)=4v-7+3(3v+4)
We move all terms to the left:
-5(v+2)-(4v-7+3(3v+4))=0
We multiply parentheses
-5v-(4v-7+3(3v+4))-10=0
We calculate terms in parentheses: -(4v-7+3(3v+4)), so:
4v-7+3(3v+4)
determiningTheFunctionDomain 4v+3(3v+4)-7
We multiply parentheses
4v+9v+12-7
We add all the numbers together, and all the variables
13v+5
Back to the equation:
-(13v+5)
We get rid of parentheses
-5v-13v-5-10=0
We add all the numbers together, and all the variables
-18v-15=0
We move all terms containing v to the left, all other terms to the right
-18v=15
v=15/-18
v=-5/6

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