-5(v+2)=5v-6+4(2v+2)

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Solution for -5(v+2)=5v-6+4(2v+2) equation: 



-5(v+2)=5v-6+4(2v+2)

We move all terms to the left:

-5(v+2)-(5v-6+4(2v+2))=0

We multiply parentheses

-5v-(5v-6+4(2v+2))-10=0



We calculate terms in parentheses: -(5v-6+4(2v+2)), so:

5v-6+4(2v+2)

determiningTheFunctionDomain
5v+4(2v+2)-6

We multiply parentheses

5v+8v+8-6

We add all the numbers together, and all the variables

13v+2

Back to the equation:

-(13v+2)



We get rid of parentheses

-5v-13v-2-10=0

We add all the numbers together, and all the variables

-18v-12=0

We move all terms containing v to the left, all other terms to the right

-18v=12

v=12/-18

v=-2/3

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