-5(v+2)=v-3+2(6v+4)

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Solution for -5(v+2)=v-3+2(6v+4) equation: 



-5(v+2)=v-3+2(6v+4)

We move all terms to the left:

-5(v+2)-(v-3+2(6v+4))=0

We multiply parentheses

-5v-(v-3+2(6v+4))-10=0



We calculate terms in parentheses: -(v-3+2(6v+4)), so:

v-3+2(6v+4)

determiningTheFunctionDomain
v+2(6v+4)-3

We multiply parentheses

v+12v+8-3

We add all the numbers together, and all the variables

13v+5

Back to the equation:

-(13v+5)



We get rid of parentheses

-5v-13v-5-10=0

We add all the numbers together, and all the variables

-18v-15=0

We move all terms containing v to the left, all other terms to the right

-18v=15

v=15/-18

v=-5/6

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