-5(v+4)=v-4+2(4v+1)

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Solution for -5(v+4)=v-4+2(4v+1) equation: 



-5(v+4)=v-4+2(4v+1)

We move all terms to the left:

-5(v+4)-(v-4+2(4v+1))=0

We multiply parentheses

-5v-(v-4+2(4v+1))-20=0



We calculate terms in parentheses: -(v-4+2(4v+1)), so:

v-4+2(4v+1)

determiningTheFunctionDomain
v+2(4v+1)-4

We multiply parentheses

v+8v+2-4

We add all the numbers together, and all the variables

9v-2

Back to the equation:

-(9v-2)



We get rid of parentheses

-5v-9v+2-20=0

We add all the numbers together, and all the variables

-14v-18=0

We move all terms containing v to the left, all other terms to the right

-14v=18

v=18/-14

v=-1+2/7

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