-5(v-3)=39-2v

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Solution for -5(v-3)=39-2v equation: 



-5(v-3)=39-2v

We move all terms to the left:

-5(v-3)-(39-2v)=0

We add all the numbers together, and all the variables

-5(v-3)-(-2v+39)=0

We multiply parentheses

-5v-(-2v+39)+15=0

We get rid of parentheses

-5v+2v-39+15=0

We add all the numbers together, and all the variables

-3v-24=0

We move all terms containing v to the left, all other terms to the right

-3v=24

v=24/-3

v=-8

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