-5(w+1)=4w-1+3(3w+4)

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Solution for -5(w+1)=4w-1+3(3w+4) equation: 



-5(w+1)=4w-1+3(3w+4)

We move all terms to the left:

-5(w+1)-(4w-1+3(3w+4))=0

We multiply parentheses

-5w-(4w-1+3(3w+4))-5=0



We calculate terms in parentheses: -(4w-1+3(3w+4)), so:

4w-1+3(3w+4)

determiningTheFunctionDomain
4w+3(3w+4)-1

We multiply parentheses

4w+9w+12-1

We add all the numbers together, and all the variables

13w+11

Back to the equation:

-(13w+11)



We get rid of parentheses

-5w-13w-11-5=0

We add all the numbers together, and all the variables

-18w-16=0

We move all terms containing w to the left, all other terms to the right

-18w=16

w=16/-18

w=-8/9

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