-5(w+3)=6w-5+2(2w+1)

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Solution for -5(w+3)=6w-5+2(2w+1) equation: 



-5(w+3)=6w-5+2(2w+1)

We move all terms to the left:

-5(w+3)-(6w-5+2(2w+1))=0

We multiply parentheses

-5w-(6w-5+2(2w+1))-15=0



We calculate terms in parentheses: -(6w-5+2(2w+1)), so:

6w-5+2(2w+1)

determiningTheFunctionDomain
6w+2(2w+1)-5

We multiply parentheses

6w+4w+2-5

We add all the numbers together, and all the variables

10w-3

Back to the equation:

-(10w-3)



We get rid of parentheses

-5w-10w+3-15=0

We add all the numbers together, and all the variables

-15w-12=0

We move all terms containing w to the left, all other terms to the right

-15w=12

w=12/-15

w=-4/5

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