-5(w+3)=9w-1+2(2w+1)

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Solution for -5(w+3)=9w-1+2(2w+1) equation: 



-5(w+3)=9w-1+2(2w+1)

We move all terms to the left:

-5(w+3)-(9w-1+2(2w+1))=0

We multiply parentheses

-5w-(9w-1+2(2w+1))-15=0



We calculate terms in parentheses: -(9w-1+2(2w+1)), so:

9w-1+2(2w+1)

determiningTheFunctionDomain
9w+2(2w+1)-1

We multiply parentheses

9w+4w+2-1

We add all the numbers together, and all the variables

13w+1

Back to the equation:

-(13w+1)



We get rid of parentheses

-5w-13w-1-15=0

We add all the numbers together, and all the variables

-18w-16=0

We move all terms containing w to the left, all other terms to the right

-18w=16

w=16/-18

w=-8/9

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