-5(w+9)(w+3)=0

Solution for -5(w+9)(w+3)=0 equation:

-5(w+9)(w+3)=0

We multiply parentheses ..

-5(+w^2+3w+9w+27)=0

We multiply parentheses

-5w^2-15w-45w-135=0

We add all the numbers together, and all the variables

-5w^2-60w-135=0

a = -5; b = -60; c = -135;
Δ = b2-4ac
Δ = -602-4·(-5)·(-135)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-30}{2*-5}=\frac{30}{-10}
=-3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+30}{2*-5}=\frac{90}{-10}
=-9
$