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-5(x+1)=2x-5+2(4x+5)
We move all terms to the left:
-5(x+1)-(2x-5+2(4x+5))=0
We multiply parentheses
-5x-(2x-5+2(4x+5))-5=0
We calculate terms in parentheses: -(2x-5+2(4x+5)), so:We get rid of parentheses
2x-5+2(4x+5)
determiningTheFunctionDomain 2x+2(4x+5)-5
We multiply parentheses
2x+8x+10-5
We add all the numbers together, and all the variables
10x+5
Back to the equation:
-(10x+5)
-5x-10x-5-5=0
We add all the numbers together, and all the variables
-15x-10=0
We move all terms containing x to the left, all other terms to the right
-15x=10
x=10/-15
x=-2/3
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