-5(x+2)-x-2=-6(x+3)+6

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Solution for -5(x+2)-x-2=-6(x+3)+6 equation: 



-5(x+2)-x-2=-6(x+3)+6

We move all terms to the left:

-5(x+2)-x-2-(-6(x+3)+6)=0

We add all the numbers together, and all the variables

-1x-5(x+2)-(-6(x+3)+6)-2=0

We multiply parentheses

-1x-5x-(-6(x+3)+6)-10-2=0



We calculate terms in parentheses: -(-6(x+3)+6), so:

-6(x+3)+6

We multiply parentheses

-6x-18+6

We add all the numbers together, and all the variables

-6x-12

Back to the equation:

-(-6x-12)



We add all the numbers together, and all the variables

-6x-(-6x-12)-12=0

We get rid of parentheses

-6x+6x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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