-5(x-1)+(x-5)=-7(x-1)-5(3x-8)+x

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Solution for -5(x-1)+(x-5)=-7(x-1)-5(3x-8)+x equation: 



-5(x-1)+(x-5)=-7(x-1)-5(3x-8)+x

We move all terms to the left:

-5(x-1)+(x-5)-(-7(x-1)-5(3x-8)+x)=0

We multiply parentheses

-5x+(x-5)-(-7(x-1)-5(3x-8)+x)+5=0

We get rid of parentheses

-5x+x-(-7(x-1)-5(3x-8)+x)-5+5=0



We calculate terms in parentheses: -(-7(x-1)-5(3x-8)+x), so:

-7(x-1)-5(3x-8)+x

We add all the numbers together, and all the variables

x-7(x-1)-5(3x-8)

We multiply parentheses

x-7x-15x+7+40

We add all the numbers together, and all the variables

-21x+47

Back to the equation:

-(-21x+47)



We add all the numbers together, and all the variables

-4x-(-21x+47)=0

We get rid of parentheses

-4x+21x-47=0

We add all the numbers together, and all the variables

17x-47=0

We move all terms containing x to the left, all other terms to the right

17x=47

x=47/17

x=2+13/17

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