-5(x-1)+(x-5)=-7(x-1)-5(3x-8)+x

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Solution for -5(x-1)+(x-5)=-7(x-1)-5(3x-8)+x equation:



-5(x-1)+(x-5)=-7(x-1)-5(3x-8)+x
We move all terms to the left:
-5(x-1)+(x-5)-(-7(x-1)-5(3x-8)+x)=0
We multiply parentheses
-5x+(x-5)-(-7(x-1)-5(3x-8)+x)+5=0
We get rid of parentheses
-5x+x-(-7(x-1)-5(3x-8)+x)-5+5=0
We calculate terms in parentheses: -(-7(x-1)-5(3x-8)+x), so:
-7(x-1)-5(3x-8)+x
We add all the numbers together, and all the variables
x-7(x-1)-5(3x-8)
We multiply parentheses
x-7x-15x+7+40
We add all the numbers together, and all the variables
-21x+47
Back to the equation:
-(-21x+47)
We add all the numbers together, and all the variables
-4x-(-21x+47)=0
We get rid of parentheses
-4x+21x-47=0
We add all the numbers together, and all the variables
17x-47=0
We move all terms containing x to the left, all other terms to the right
17x=47
x=47/17
x=2+13/17

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