-5(x-2)+4x=x(3-x)-4(x-2)+x2+2

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Solution for -5(x-2)+4x=x(3-x)-4(x-2)+x2+2 equation: 



-5(x-2)+4x=x(3-x)-4(x-2)+x2+2

We move all terms to the left:

-5(x-2)+4x-(x(3-x)-4(x-2)+x2+2)=0

We add all the numbers together, and all the variables

-5(x-2)+4x-(x(-1x+3)-4(x-2)+x2+2)=0

We add all the numbers together, and all the variables

4x-5(x-2)-(x(-1x+3)-4(x-2)+x2+2)=0

We multiply parentheses

4x-5x-(x(-1x+3)-4(x-2)+x2+2)+10=0



We calculate terms in parentheses: -(x(-1x+3)-4(x-2)+x2+2), so:

x(-1x+3)-4(x-2)+x2+2

We add all the numbers together, and all the variables

x^2+x(-1x+3)-4(x-2)+2

We multiply parentheses

x^2-1x^2+3x-4x+8+2

We add all the numbers together, and all the variables

-1x+10

Back to the equation:

-(-1x+10)



We add all the numbers together, and all the variables

-1x-(-1x+10)+10=0

We get rid of parentheses

-1x+1x-10+10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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