-5(x-2)-2=2(x+1)-5

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Solution for -5(x-2)-2=2(x+1)-5 equation: 



-5(x-2)-2=2(x+1)-5

We move all terms to the left:

-5(x-2)-2-(2(x+1)-5)=0

We multiply parentheses

-5x-(2(x+1)-5)+10-2=0



We calculate terms in parentheses: -(2(x+1)-5), so:

2(x+1)-5

We multiply parentheses

2x+2-5

We add all the numbers together, and all the variables

2x-3

Back to the equation:

-(2x-3)



We add all the numbers together, and all the variables

-5x-(2x-3)+8=0

We get rid of parentheses

-5x-2x+3+8=0

We add all the numbers together, and all the variables

-7x+11=0

We move all terms containing x to the left, all other terms to the right

-7x=-11

x=-11/-7

x=1+4/7

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