-5(x-4)(x+4)=0

Solution for -5(x-4)(x+4)=0 equation:

Simplifying
-5(x + -4)(x + 4) = 0

Reorder the terms:
-5(-4 + x)(x + 4) = 0

Reorder the terms:
-5(-4 + x)(4 + x) = 0

Multiply (-4 + x) * (4 + x)
-5(-4(4 + x) + x(4 + x)) = 0
-5((4 * -4 + x * -4) + x(4 + x)) = 0
-5((-16 + -4x) + x(4 + x)) = 0
-5(-16 + -4x + (4 * x + x * x)) = 0
-5(-16 + -4x + (4x + x2)) = 0

Combine like terms: -4x + 4x = 0
-5(-16 + 0 + x2) = 0
-5(-16 + x2) = 0
(-16 * -5 + x2 * -5) = 0
(80 + -5x2) = 0

Solving
80 + -5x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-80' to each side of the equation.
80 + -80 + -5x2 = 0 + -80

Combine like terms: 80 + -80 = 0
0 + -5x2 = 0 + -80
-5x2 = 0 + -80

Combine like terms: 0 + -80 = -80
-5x2 = -80

Divide each side by '-5'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}