-5(x-4)+6x-19=3

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Solution for -5(x-4)+6x-19=3 equation: 



-5(x-4)+6x-19=3

We move all terms to the left:

-5(x-4)+6x-19-(3)=0

We add all the numbers together, and all the variables

6x-5(x-4)-22=0

We multiply parentheses

6x-5x+20-22=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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