-5(y+1)+4(3y-5)=6(y-6)+11

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Solution for -5(y+1)+4(3y-5)=6(y-6)+11 equation: 



-5(y+1)+4(3y-5)=6(y-6)+11

We move all terms to the left:

-5(y+1)+4(3y-5)-(6(y-6)+11)=0

We multiply parentheses

-5y+12y-(6(y-6)+11)-5-20=0



We calculate terms in parentheses: -(6(y-6)+11), so:

6(y-6)+11

We multiply parentheses

6y-36+11

We add all the numbers together, and all the variables

6y-25

Back to the equation:

-(6y-25)



We add all the numbers together, and all the variables

7y-(6y-25)-25=0

We get rid of parentheses

7y-6y+25-25=0

We add all the numbers together, and all the variables

y=0

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