-5(y+1)=5y-3+2(2y+7)

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Solution for -5(y+1)=5y-3+2(2y+7) equation: 



-5(y+1)=5y-3+2(2y+7)

We move all terms to the left:

-5(y+1)-(5y-3+2(2y+7))=0

We multiply parentheses

-5y-(5y-3+2(2y+7))-5=0



We calculate terms in parentheses: -(5y-3+2(2y+7)), so:

5y-3+2(2y+7)

determiningTheFunctionDomain
5y+2(2y+7)-3

We multiply parentheses

5y+4y+14-3

We add all the numbers together, and all the variables

9y+11

Back to the equation:

-(9y+11)



We get rid of parentheses

-5y-9y-11-5=0

We add all the numbers together, and all the variables

-14y-16=0

We move all terms containing y to the left, all other terms to the right

-14y=16

y=16/-14

y=-1+1/7

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