-5(y+2)=-2(2y-1)+9y

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Solution for -5(y+2)=-2(2y-1)+9y equation: 



-5(y+2)=-2(2y-1)+9y

We move all terms to the left:

-5(y+2)-(-2(2y-1)+9y)=0

We multiply parentheses

-5y-(-2(2y-1)+9y)-10=0



We calculate terms in parentheses: -(-2(2y-1)+9y), so:

-2(2y-1)+9y

We add all the numbers together, and all the variables

9y-2(2y-1)

We multiply parentheses

9y-4y+2

We add all the numbers together, and all the variables

5y+2

Back to the equation:

-(5y+2)



We get rid of parentheses

-5y-5y-2-10=0

We add all the numbers together, and all the variables

-10y-12=0

We move all terms containing y to the left, all other terms to the right

-10y=12

y=12/-10

y=-1+1/5

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