-5(y+2)=-2(3y-4)+5y

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Solution for -5(y+2)=-2(3y-4)+5y equation: 



-5(y+2)=-2(3y-4)+5y

We move all terms to the left:

-5(y+2)-(-2(3y-4)+5y)=0

We multiply parentheses

-5y-(-2(3y-4)+5y)-10=0



We calculate terms in parentheses: -(-2(3y-4)+5y), so:

-2(3y-4)+5y

We add all the numbers together, and all the variables

5y-2(3y-4)

We multiply parentheses

5y-6y+8

We add all the numbers together, and all the variables

-1y+8

Back to the equation:

-(-1y+8)



We get rid of parentheses

-5y+1y-8-10=0

We add all the numbers together, and all the variables

-4y-18=0

We move all terms containing y to the left, all other terms to the right

-4y=18

y=18/-4

y=-4+1/2

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