-5(y+3)=9y-5+2(2y+3)

Solution for -5(y+3)=9y-5+2(2y+3) equation:

-5(y+3)=9y-5+2(2y+3)

We move all terms to the left:

-5(y+3)-(9y-5+2(2y+3))=0

We multiply parentheses

-5y-(9y-5+2(2y+3))-15=0


We calculate terms in parentheses: -(9y-5+2(2y+3)), so:

9y-5+2(2y+3)

determiningTheFunctionDomain
9y+2(2y+3)-5

We multiply parentheses

9y+4y+6-5

We add all the numbers together, and all the variables

13y+1

Back to the equation:

-(13y+1)


We get rid of parentheses

-5y-13y-1-15=0

We add all the numbers together, and all the variables

-18y-16=0

We move all terms containing y to the left, all other terms to the right

-18y=16

y=16/-18

y=-8/9