-5(y-3y)+6=-4(3y-y)+7+17y

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Solution for -5(y-3y)+6=-4(3y-y)+7+17y equation: 



-5(y-3y)+6=-4(3y-y)+7+17y

We move all terms to the left:

-5(y-3y)+6-(-4(3y-y)+7+17y)=0

We add all the numbers together, and all the variables

-5(-2y)-(-4(+2y)+7+17y)+6=0

We multiply parentheses

10y-(-4(+2y)+7+17y)+6=0



We calculate terms in parentheses: -(-4(+2y)+7+17y), so:

-4(+2y)+7+17y

determiningTheFunctionDomain
-4(+2y)+17y+7

We add all the numbers together, and all the variables

17y-4(+2y)+7

We multiply parentheses

17y-8y+7

We add all the numbers together, and all the variables

9y+7

Back to the equation:

-(9y+7)



We get rid of parentheses

10y-9y-7+6=0

We add all the numbers together, and all the variables

y-1=0

We move all terms containing y to the left, all other terms to the right

y=1

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