-5(y-3y)+7=-4(2y-y)+2+13y

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Solution for -5(y-3y)+7=-4(2y-y)+2+13y equation: 



-5(y-3y)+7=-4(2y-y)+2+13y

We move all terms to the left:

-5(y-3y)+7-(-4(2y-y)+2+13y)=0

We add all the numbers together, and all the variables

-5(-2y)-(-4(+y)+2+13y)+7=0

We multiply parentheses

10y-(-4(+y)+2+13y)+7=0



We calculate terms in parentheses: -(-4(+y)+2+13y), so:

-4(+y)+2+13y

determiningTheFunctionDomain
-4(+y)+13y+2

We add all the numbers together, and all the variables

13y-4(+y)+2

We multiply parentheses

13y-4y+2

We add all the numbers together, and all the variables

9y+2

Back to the equation:

-(9y+2)



We get rid of parentheses

10y-9y-2+7=0

We add all the numbers together, and all the variables

y+5=0

We move all terms containing y to the left, all other terms to the right

y=-5

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