-5(z+1)+3(3z-5)=3(z-3)+8

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Solution for -5(z+1)+3(3z-5)=3(z-3)+8 equation:


-5(z+1)+3(3z-5)=3(z-3)+8

We simplify the equation to the form, which is simple to understand 
-5(z+1)+3(3z-5)=3(z-3)+8

Reorder the terms in parentheses
+(-5z-5)+3*(3z-5)=3*(z-3)+8

Remove unnecessary parentheses
-5z-5+3+*(+3z-5+)=+3+*(+z-3+)+8

Reorder the terms in parentheses
-5z-5+(+9z-15)=3*(z-3)+8

Remove unnecessary parentheses
-5z-5+9z-15=+3+*(+z-3+)+8

Reorder the terms in parentheses
-5z-5+9z-15=+(+3z-9)+8

Remove unnecessary parentheses
-5z-5+9z-15=+3z-9+8

We move all terms containing z to the left and all other terms to the right. 
-5z+9z-3z=-9+8+5+15

We simplify left and right side of the equation. 
+1z=+19

We divide both sides of the equation by 1 to get z. 
z=19

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