-5+(-6g-4);g=-2

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Solution for -5+(-6g-4);g=-2 equation: 



-5+(-6g-4)g=-2

We move all terms to the left:

-5+(-6g-4)g-(-2)=0

We add all the numbers together, and all the variables

(-6g-4)g-3=0

We multiply parentheses

-6g^2-4g-3=0

a = -6; b = -4; c = -3;
Δ = b2-4ac
Δ = -42-4·(-6)·(-3)
Δ = -56
Delta is less than zero, so there is no solution for the equation

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