-5+2(1+3a)=3(a-11)

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Solution for -5+2(1+3a)=3(a-11) equation: 



-5+2(1+3a)=3(a-11)

We move all terms to the left:

-5+2(1+3a)-(3(a-11))=0

We add all the numbers together, and all the variables

2(3a+1)-(3(a-11))-5=0

We multiply parentheses

6a-(3(a-11))+2-5=0



We calculate terms in parentheses: -(3(a-11)), so:

3(a-11)

We multiply parentheses

3a-33

Back to the equation:

-(3a-33)



We add all the numbers together, and all the variables

6a-(3a-33)-3=0

We get rid of parentheses

6a-3a+33-3=0

We add all the numbers together, and all the variables

3a+30=0

We move all terms containing a to the left, all other terms to the right

3a=-30

a=-30/3

a=-10

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