-5+2(10b+2)=31

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Solution for -5+2(10b+2)=31 equation: 



-5+2(10b+2)=31

We move all terms to the left:

-5+2(10b+2)-(31)=0

We add all the numbers together, and all the variables

2(10b+2)-36=0

We multiply parentheses

20b+4-36=0

We add all the numbers together, and all the variables

20b-32=0

We move all terms containing b to the left, all other terms to the right

20b=32

b=32/20

b=1+3/5

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