-5+2(3+g)=4(g+1)

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Solution for -5+2(3+g)=4(g+1) equation: 



-5+2(3+g)=4(g+1)

We move all terms to the left:

-5+2(3+g)-(4(g+1))=0

We add all the numbers together, and all the variables

2(g+3)-(4(g+1))-5=0

We multiply parentheses

2g-(4(g+1))+6-5=0



We calculate terms in parentheses: -(4(g+1)), so:

4(g+1)

We multiply parentheses

4g+4

Back to the equation:

-(4g+4)



We add all the numbers together, and all the variables

2g-(4g+4)+1=0

We get rid of parentheses

2g-4g-4+1=0

We add all the numbers together, and all the variables

-2g-3=0

We move all terms containing g to the left, all other terms to the right

-2g=3

g=3/-2

g=-1+1/2

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