-5+5(2n-1)=4(n-1)

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Solution for -5+5(2n-1)=4(n-1) equation: 



-5+5(2n-1)=4(n-1)

We move all terms to the left:

-5+5(2n-1)-(4(n-1))=0

We multiply parentheses

10n-(4(n-1))-5-5=0



We calculate terms in parentheses: -(4(n-1)), so:

4(n-1)

We multiply parentheses

4n-4

Back to the equation:

-(4n-4)



We add all the numbers together, and all the variables

10n-(4n-4)-10=0

We get rid of parentheses

10n-4n+4-10=0

We add all the numbers together, and all the variables

6n-6=0

We move all terms containing n to the left, all other terms to the right

6n=6

n=6/6

n=1

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