-5+b2=-b

Solution for -5+b2=-b equation:

-5+b2=-b

We move all terms to the left:

-5+b2-(-b)=0

We add all the numbers together, and all the variables

b2-(-1b)-5=0

We add all the numbers together, and all the variables

b^2-(-1b)-5=0

We get rid of parentheses

b^2+1b-5=0

We add all the numbers together, and all the variables

b^2+b-5=0

a = 1; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·1·(-5)
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{21}}{2*1}=\frac{-1-\sqrt{21}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{21}}{2*1}=\frac{-1+\sqrt{21}}{2}
$