-5-2(y-5)=4y-2(2y+4)-3

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Solution for -5-2(y-5)=4y-2(2y+4)-3 equation: 



-5-2(y-5)=4y-2(2y+4)-3

We move all terms to the left:

-5-2(y-5)-(4y-2(2y+4)-3)=0

We multiply parentheses

-2y-(4y-2(2y+4)-3)+10-5=0



We calculate terms in parentheses: -(4y-2(2y+4)-3), so:

4y-2(2y+4)-3

We multiply parentheses

4y-4y-8-3

We add all the numbers together, and all the variables

-11

Back to the equation:

-(-11)



We add all the numbers together, and all the variables

-2y+16=0

We move all terms containing y to the left, all other terms to the right

-2y=-16

y=-16/-2

y=+8

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