-5-3(1-4b)=40+6b

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Solution for -5-3(1-4b)=40+6b equation: 



-5-3(1-4b)=40+6b

We move all terms to the left:

-5-3(1-4b)-(40+6b)=0

We add all the numbers together, and all the variables

-3(-4b+1)-(6b+40)-5=0

We multiply parentheses

12b-(6b+40)-3-5=0

We get rid of parentheses

12b-6b-40-3-5=0

We add all the numbers together, and all the variables

6b-48=0

We move all terms containing b to the left, all other terms to the right

6b=48

b=48/6

b=8

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